Let's say I have 48 candies spread in 3 bags. If from the first bag I pass to the second as many candies as there are in the third and then I pass 6 candies from the second to the first, and finally, I pass 4 candies from the second bag to the third, the result is that I now have the same amount of candies in all three bags.

**How many candies did he initially have in each bag?**

#### Solution

If we do all the operations in reverse, knowing that finally each bag will have 16 candies, we will realize that:

The 1st bag initially had 22 candies, the 2nd bag had 14 candies and the 3rd bag had 12 candies.