We have 8 numbers: 2 ones, 2 doses, 2 three, 2 four. They must be placed in such a way that between the 2 ones there is only one number, between the 2 doses there are two numbers, between the 2 three, three numbers and between the 2 four, four numbers.
How to place them?
Solution
You have to distribute them like this:
4 1 3 1 2 4 3 2
Or vice versa:
2 3 4 2 1 3 1 4
